How to identify the position in which a value is NaN

I want to be able to identify the position in which a value is NaN

If I have:

x = [1 NaN 3 4 5 NaN 7 8 9 10]

In which the second and sixt position are NaN

something that gives me an answer = [ 2 , 6 ] is what I am looking for.

I usually use the "find" such as find(x==3) would return = 3 (because it is at the third position), but now I want to apply it for NaN

Not sure how that could be done, wonder if anybody can help me. Thanks in advance!

Answer 1

[Voss]

You can use the isnan function:

x = [1   NaN     3     4     5   NaN     7     8     9    10];

find(isnan(x))

ans = 1×2

2 6

[Alfredo Scigliani]

Yes! Thank you so much!

[Voss]

You're welcome!