# How to give trail to particles/ How to fade out plots with time (complex example)

26 views (last 30 days)

Show older comments

Inspired from a webproject I have created this n-body-simulation:

First of a function to acces on:

% calculating acceleration of particles

function [a] = getAcc(pos,mass,softening)

% gravitation constant

G = 1;

% Number of particles

N = size(pos,1);

% acceleration matrix

a = zeros(N,3);

% loop to fill in acceleration by interaction with each particle

for i = 1:N

for j = 1:N

if i ~= j

dx = pos(j,1)-pos(i,1);

dy = pos(j,2)-pos(i,2);

dz = pos(j,3)-pos(i,3);

dr = (dx.^2 + dy.^2 + dz.^2+ softening.^2).^(-3/2);

a(i,1) = a(i,1) + G * mass(j,1) * (dr * dx);

a(i,2) = a(i,2) + G * mass(j,1) * (dr * dy);

a(i,3) = a(i,3) + G * mass(j,1) * (dr * dz);

end

end

end

followed by the Main script:

clear

%% setting initial conditions

% Number of particles

N = 10;

% max distance between partices at start

rmax = 4;

pos = rmax * rand(N,3);

% max velocity for particles

vmax = 1;

vel = vmax * rand(N,3);

% max mass of particles

mmax = 5;

mass = mmax * ones(N,1);

% minimal distance parameter

softening = 0.5;

% calculating acceleration of particles

acc = getAcc(pos,mass,softening);

% selecting start time

t_start = 0;

% selecting timestep

dt = 0.04;

% selecting end time

t_end = 250;

% initializing figure

figure

grid on

view(3)

%% starting main loop

for i = 1:t_end

vel = vel + acc * dt/2;

[pos] = pos + vel * dt;

acc = getAcc(pos, mass, softening);

vel = vel + acc * dt/2;

t_start = t_start + dt;

hold all

for j = 1:N

plot3(pos(j,1),pos(j,2),pos(j,3),'b.','MarkerSize',4)

end

pause(0.005)

end

However I'm running into a problem here: the particles path will not disapear gradually since all positions are hold. I saw some clever ways implementing a fade but I'm not able adapting it here. Maybe someone brave enough working through all the code may give some advises.

##### 0 Comments

### Accepted Answer

DGM
on 7 Apr 2022

Edited: DGM
on 7 Apr 2022

Here's one way using scatter3()

% setting initial conditions

% Number of particles

N = 3; % i'm using fewer points for ease of viewing

% max distance between partices at start

rmax = 4;

pos = rmax * rand(N,3);

% max velocity for particles

vmax = 1;

vel = vmax * rand(N,3);

% max mass of particles

mmax = 5;

mass = mmax * ones(N,1);

% minimal distance parameter

softening = 0.5;

% calculating acceleration of particles

acc = getAcc(pos,mass,softening);

% selecting start time

t_start = 0;

% selecting timestep

dt = 0.04;

% selecting end time

t_end = 250;

% initializing figure

grid on

view(3)

% preallocate outputs

xpos = zeros(N,t_end);

ypos = zeros(N,t_end);

zpos = zeros(N,t_end);

% starting main loop

for i = 1:t_end

vel = vel + acc * dt/2;

[pos] = pos + vel * dt;

acc = getAcc(pos, mass, softening);

vel = vel + acc * dt/2;

t_start = t_start + dt;

% store outputs

xpos(:,i) = pos(:,1);

ypos(:,i) = pos(:,2);

zpos(:,i) = pos(:,3);

end

% each trajectory has its own solid color

cmap = hsv(N);

% alpha is a linear gradient from 1 to 0

alph = fliplr(linspace(0,1,t_end));

for ks = 1:N

hs = scatter3(xpos(ks,:),ypos(ks,:),zpos(ks,:),10,cmap(ks,:),'filled');

hold on;

hs.AlphaData = alph;

hs.AlphaDataMapping = 'none';

hs.MarkerFaceAlpha = 'flat';

end

function [a] = getAcc(pos,mass,softening)

% gravitation constant

G = 1;

% Number of particles

N = size(pos,1);

% acceleration matrix

a = zeros(N,3);

% loop to fill in acceleration by interaction with each particle

for i = 1:N

for j = 1:N

if i ~= j

dx = pos(j,1)-pos(i,1);

dy = pos(j,2)-pos(i,2);

dz = pos(j,3)-pos(i,3);

dr = (dx.^2 + dy.^2 + dz.^2+ softening.^2).^(-3/2);

a(i,1) = a(i,1) + G * mass(j,1) * (dr * dx);

a(i,2) = a(i,2) + G * mass(j,1) * (dr * dy);

a(i,3) = a(i,3) + G * mass(j,1) * (dr * dz);

end

end

end

end

I imagine this isn't really what you want though. I imagine you want something that fades points dynamically as new points are plotted. That can be done, but it'll be slow.

##### 3 Comments

DGM
on 19 Apr 2022

### More Answers (1)

Image Analyst
on 6 Apr 2022

##### 0 Comments

### See Also

### Categories

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!