How to calculate the norm of the transfer function in frequency domain?
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To calculate the norm of the transfer function by substituting s=jω is troublesome, especially for some complicated transfer functions. Is there a way to calculate the norm directly? Thanks!
For example, transfer funciton:
Thus we can plot the figure in frequency domain,
G1_N=0.25e-2 .* omega .^ 2 + 0.1e1;
G1_D=((2 .* omega) - 0.15e0 .* (omega .^ 3)) .^ 2 + (0.1e1 + 0.5e-2 .* (omega .^ 4) - (omega .^ 2)) .^ 2;
G1=sqrt(G1_N ./ G1_D);
William Rose on 13 Mar 2022
You don't need to multiply the function by its complex conjugate to get a purely real denominator. Just divide complex numerator by the complex denominator, to get a new complex number, and take the abs() of it.