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How to remove repeated values mantaining the first one from an array ?
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I have something like:
10000111111111011011100000111011000111111011000000010101011111111....
how to:
00000100000000010010000000100010000100000010000000000000010000000....
The second repetition makes the beggining of a series.
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Answers (2)
Sean de Wolski
on 8 Dec 2014
abs(diff('0000111001111101101'))
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Guillaume
on 8 Dec 2014
Hum, it looks like the OP only wants the transitions from 0 to 1 (which would be diff(x) > 0) but only when there's more than one consecutive 1 (which is not as simple unfortunately).
Guillaume
on 8 Dec 2014
s = '10000111111111011011100000111011000111111011000000010101011111111'
o = char('0' + ([0 diff(s) > 0] & [~diff(s) 0]))
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