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How to find elements of first matrix based on second matrix?

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I have two matrices A and B
A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
How to find entries of A coresponsing to '1' in B
result = [1 4 6 8 9 10];
  1 Comment
Stephen23
Stephen23 on 23 Feb 2022
Note that FIND is not required, logical indexing is simpler and more efficient:
A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
C = A(B==1)
C = 1×6
1 4 6 8 9 10

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Answers (1)

Arif Hoq
Arif Hoq on 23 Feb 2022
use find function
A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
result=A(find(B==1))
result = 1×6
1 4 6 8 9 10
  2 Comments
Stephen23
Stephen23 on 23 Feb 2022
Edited: Stephen23 on 23 Feb 2022
FIND is not required, logical indexing is simpler and more efficient:
A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
C = A(B==1)
C = 1×6
1 4 6 8 9 10

Sign in to comment.

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