regroupe the results in a matrix

hii i have this

f=   1     0
     0     1
     0     2 
     1     3
     0     4 
     1     5
     1     6
     0     7

this indicate the numbers from 0 to 7 in decimal i want to regroupe the 1 in a matrix and at the same time tell which number it is and do the same thing with 0 i have a mistake somewhere here's the program

N=8;
r=3;
A=zeros(N,r);
Q=zeros(N,1);
for k=0:1:N-1
A(k+1,:)=dec2bin(k,r)-'0';
Q(k+1,1)=xor(xor(A(k+1,1),A(k+1,2)),A(k+1,3));
f=xor(Q,1);
end
for k=0:1:N-1
if f(k+1)==1
 se=k
 S(k+1,1)=se
else
ss=k
C(k+1,1)=ss
end
end
S =

     0
     0
     0
     0
     3
     5
     0
     6

C =

     0
     1
     2
     0
     4
     0
     0
     7
 i don't know how to do to delete the 0 i just want 0356 and 1247 to appears
i hope you understand me

Answer 1

[Thorsten]

Ok, here is my 2nd solution. There's also a faster way to compute f, I think:

f = 1 - (mod(sum(A'), 2) == 1);
x = 0:7;

s = x(~logical(f));
c = x(logical(f));

[Dija]

Thank you so much can u ask another question please!

[Thorsten]

Sure, but please start a new question to that others can help you, too.

[Dija]

it is about this program too and i guess that you can understand me more than others it is okey if you can't help me but i will try with you first :)

how can i discard any bianry digit i want in A for example if i discard the first one in A

A =
   0     0     0
   0     0     1
   0     1     0
   0     1     1
   1     0     0
   1     0     1
   1     1     0
   1     1     1

i want to get this

A =

          0     0
          0     1
          1     0
          1     1
          0     0
          0     1
          1     0
          1     1

Answer 2

[dpb]

>> s=find(f(:,1))
s =
   1
   4
   6
   7
>> c=f(s,2)
c =
   0
   3
   5
   6
>>

Looks like your desired S above is from some other sample dataset...f(2,1)==0

ADDENDUM

OK, following your comment/plea; the complementary is by the above

s=find(f(:,1);
c=f(s,2);
s=f(find(f(:,1)==0,2));

This is a little convoluted; I did it that way because as noted I thought you were looking for the position in the original vector, not the two results.

More straightforward in the latter case is to use logical addressing instead of find --

ix=f(:,1)==1);  % the '1' location vector
s=f(ix,2);
c=f(~ix,2);

[Dija]

it doesnt work i want to regroupe {0 3 5 6} together and {1 2 4 7}

[dpb]

What rule puts [1 2 4 7] together? The positions that correspond to the value '1' in f(:,1) aren't those.

Oh; I see -- it's not the positions of the '1' entries corresponding it's the complementary values. That's simply returning the '0' rows instead of '1'. See updated Answer.

[Dija]

it doesnt work too

[dpb]

Does too...

>> f
f =
   1     0
   0     1
   0     2
   1     3
   0     4
   1     5
   1     6
   0     7
>> ix=f(:,1)==1;
>> s=f(ix,2)
ans =
   0
   3
   5
   6
>> c=f(~ix,2)
c =
   1
   2
   4
   7
>>

Answer 3

[Thorsten]

x = f(:,2);
x(logical(f(:,1)))

ans =

       0
       3
       5
       6

x(~logical(f(:,1)))

ans =

       1
       2
       4
       7

[Dija]

i have this error when i run the program

Attempted to access f(:,2); index out of bounds because size(f)=[8,1].

Error in Untitled2 (line 12) x = f(:,2);

[Thorsten]

I used the f in your example which is of size 8 x 2:

f = [1     0
     0     1
     0     2 
     1     3
     0     4 
     1     5
     1     6
     0     7];

[Andrei Bobrov]

I too

[Dija]

oh i see i am sorry i was explaining that it goes from 0 to 7 i have a matrix

A =

     0     0     0
     0     0     1
     0     1     0
     0     1     1
     1     0     0
     1     0     1
     1     1     0
     1     1     1

then i calculate the xor of each digit with this program

 for k=0:1:N-1
  A(k+1,:)=dec2bin(k,r)-'0';
  Q(k+1,1)=xor(xor(A(k+1,1),A(k+1,2)),A(k+1,3));
  f=xor(Q,1);
end

and i got f

f =

     1
     0
     0
     1
     0
     1
     1
     0
Now i want to put all the 1 together and the 0 together and at the same time i want to tell which number it is
i did this program 

for k=0:1:N-1
if f(k+1)==1
 se=k;
 s(k+1,1)=se;
else
ss=k;
c(k+1,1)=ss;
end
end

and i got this results s =

     0
     0
     0
     3
     0
     5
     6

c =

     0
     1
     2
     0
     4
     0
     0
     7
know i want the results to be like this 
s =

     0
     3
     5
     6

c = 1 2 4 7 I dont know where is my mistake

here it is all the program

N=8;
r=3;
A=zeros(N,r);
Q=zeros(N,1);
for k=0:1:N-1
A(k+1,:)=dec2bin(k,r)-'0';
Q(k+1,1)=xor(xor(A(k+1,1),A(k+1,2)),A(k+1,3));
f=xor(Q,1);
end
A
f
for k=0:1:N-1
if f(k+1)==1
 se=k;
 s(k+1,1)=se;
else
ss=k;
c(k+1,1)=ss;
end
end
s
c

[dpb]

...to put all the 1 together and the 0 together and at the same time i want to tell which number it is...

That's my first solution via find

[Dija]

ive tried it but it didnt work i got this error Index exceeds matrix dimensions. Error in c=f(s,2)

beside there's a mistake in s s =

     1
     4
     6
     7

it is 1 2 4 7

[dpb]

Well, you've got to use the arrays as they're sized--I can't help you changing from the initial 8x2 to something else. It's your problem, fix up the indexing to address the data where it is. The sample problem was two columns with the index to segregate over in the first and the second column containing values. If you want them some other way, adjust the logic to address that.

[Dija]

thank you

[dpb]

Well, again we're mis-communicating on what you mean by "which number it is" -- whether it's the location in the array or the numeric value. Since you weren't happy with the latter in the demonstrated solution I thought you meant the position again which find returns.

If it's actually the numeric value then the logic array solution is the more straightforward as demonstrated with the inputs in a 2-column array. If you don't put them in the array, then use whatever is the storage for each column in place of the array.

Answer 4

[Andrei Bobrov]

S = num2str(f(f(:,1)>0,2))';
C = num2str(f(~f(:,1),2))';

[Dija]

the same error :( Index exceeds matrix dimensions.

Error in Untitled2 (line 12) S = num2str(f(f(:,1)>0,2))'