Error graphing a VVF

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Cassandra Meyer
Cassandra Meyer on 9 Feb 2022
Commented: Star Strider on 9 Feb 2022
I am trying to graph this VVF but it saying "Expected input to be one of these types: function_handle, sym Instead its type was double." What am I doing wrong?
syms t
x = (exp(-t))*sin(t)
y = (exp(-t))*cos(t)
z = 1
fplot3(x, y, z, [0, pi])

Accepted Answer

Star Strider
Star Strider on 9 Feb 2022
The ‘z’ function needs to be defined as symbolic. Without that provision, fplot3 sees it as a double, not a symbolic constant (which is what you want it to see).
Add that ...
syms t
x = (exp(-t))*sin(t)
x = 
y = (exp(-t))*cos(t)
y = 
z = sym(1)
z = 
1
fplot3(x, y, z, [0, pi])
... to get what I assume is the desired result.
.
  2 Comments
Cassandra Meyer
Cassandra Meyer on 9 Feb 2022
Yes, this is perfect. Thank you so much!
Star Strider
Star Strider on 9 Feb 2022
As always, my pleasure!

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