Equations to Matlab code
2 views (last 30 days)
Show older comments
hi
I want to convert the two equations below into Matlab code , I wrote the function below for that and I don't know if that is correct or not , specially the integral form ? any help ?
function [VI,Vw]= Modelfun(TL,TR)
dt=0.01; %sampling time
r=0.052;
L=0.306;
M=9;
I=5;
VI=(TL+TR)/ M * r;
VI=VI*dt/2; %first integral
Vw=(L*(TL-TR)) / 2 * r * I;
Vw=Vw*dt/2; %first integral
Vw=Vw*dt/2; %second integral
end
0 Comments
Accepted Answer
Torsten
on 20 Nov 2014
It is not possible simply to output (VI,Vw) given (TL,TR).
As input you need (VIold,Vwold,Vwdotold,dt,TL,TR).
The output VI,Vw and Vwdot is then calculated according to
VI=VIold+dt*(TL+TR)/(M*r)
Vw=Vwold+dt*Vwdotold
Vwdot=Vwdotold+dt*L*(TL-TR)/(2*r*I).
This would mean that your function "Modelfun" advances VI and Vw from their values at time t to time t+dt.
Best wishes
Torsten.
0 Comments
More Answers (2)
Torsten
on 18 Nov 2014
If the right-hand sides of your equations does not depend on t, the solution to your differential equations is explicitely given by
VI=VI0+(TL+TR)/(M*r)*t
Vw=Vw0+Vw0dot*t+0.5*L*(TL-TR)/(2*r*I)*t^2
where
VI0=VI at time t=0
Vw0=Vw at time t=0
Vw0dot = d/dt(Vw) at time t=0.
Best wishes
Torsten.
5 Comments
See Also
Categories
Find more on Characters and Strings in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!