Find position of the maximum value and then convert the row zeros and the position of the maximum value should become 1. just like in the image attach

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Accepted Answer

KSSV on 23 Nov 2021
A = rand(4) ;
[m,n] = size(A) ;
B = zeros(m,n) ;
[val,i] = max(A,[],2) ;
idx = sub2ind(size(A),(1:m)',i) ;
B(idx) = 1 ;
  1 Comment
Adil Sardar
Adil Sardar on 24 Nov 2021
Thank you..
This output is from simulink I saved it in a file.. Instead of saving it how to apply this method in simulink for running time so that I get the output in binary format.

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