how to calculate row values based on the previous row value of a column?

input array

a= [1,2,3,4,5,6,7,8,9,10]

the output array is as follows. where 100 is initial value we are calculating for 1. for 2 we are taking output of 1.

b= (1*100)+100 = 200

b = (2*200)+ 200 = 600

b=(3*600)+600 = 2400

like wise i need to calculate for all elements of a.

Answer 1

[Chunru]

a= [1,2,3,4,5,6,7,8,9,10];
b = 100;        % initial value
for i=1:numel(a)
    b= (a(i)*b)+b;
    fprintf("i=%2d  b=%d\n", i, b)
end

i= 1  b=200
i= 2  b=600
i= 3  b=2400
i= 4  b=12000
i= 5  b=72000
i= 6  b=504000
i= 7  b=4032000
i= 8  b=36288000
i= 9  b=362880000
i=10  b=3991680000