Input A of class cell and input B of class cell must be cell arrays of character vectors, unless one is a character vector.

I have a cell array A

2×1 cell array

{[321]}

{[640]}

and I have a cell array B, that is a 1×6 cell array.

In B,

B{:,6} contains the below elements

2×1 cell array

{[321]}

{[278]}.

I want to use ismember, to extract the value 321, that it is contaιnes in both arrays.

If I try ismember(A,B{:,6}),

it sais error because Input A of class cell and input B of class cell must be cell arrays of character vectors, unless one is a character vector.

What can I do?

Thank you very much.

[Stephen23]

Ioannis Vourvachakis' incorrectly posted "Answer" moved here:

Thank you. I have one more question.

I have a cell array A

and a cell array B

As you see, the first line (and the only one) of A is the same with the fourth line of B.

I want to create a logical condition for the existence of a line of array A same in array B.

Worth noting that this is equal to creating a a logical condition for the existence of a element in the first column of array A same in the first column in array B.

I tried ismember(A{:,1},B{:,1})

but it throws an error because Error using ismember

Too many input arguments.

Please help me

[Stephen23]

Follow-up question:

https://www.mathworks.com/matlabcentral/answers/1580109-intersect-between-a-double-and-a-complicated-cell-array

Answer 1

[Stephen23]

Why are you inefficiently storing scalar numerics in cell arrays?

Using numeric arrays would be much simpler and avoid this error.

"I want to use ismember, to extract the value 321, that it is contaιnes in both arrays."

If the goal is really to get the common members, why not just use INTERSECT? (which once again, is much easier with numeric arrays).

Given that inefficent data:

A = {321,640}

A = 1×2 cell array
    {[321]}    {[640]}

B = [cell(2,5),{321;278}]

B = 2×6 cell array
    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}    {[321]}
    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}    {[278]}

C = intersect([A{:}],[B{:,6}])

C = 321

or

X = ismember([A{:}],[B{:,6}])

X = 1×2 logical array
   1   0

D = A(X)

D = 1×1 cell array
    {[321]}

Answer 2

[Matt J]

It is puzzling that A and B are cell arrays when they could easily just be vectors. Nevertheless, they can be converted with cell2mat:

ismember(cell2mat(A),cell2mat(B{6}))