How to build a set of matrices using the for loop
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on 4 Aug 2014
Commented: Andrea Vandin
on 5 Jun 2020
Hi all, I need for building a set of matrices using the for loop; Starting from the main matrix with dimension 9x9, I want to build 8 matrices with dimension 9x2 that have the first column equal to the one of the first matrix and the second column equal to the second, the third, ..., the nineth column of the main matrix. I used the following code, but it does not work for some reason:
for i=2:9
[NewMatrix(i)]=[MainMatrix(:,1),MainMatrix(:,i)];
end
Can someone explain me what is the error in this code? Thanks in advances
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Accepted Answer
Azzi Abdelmalek
on 4 Aug 2014
Edited: Azzi Abdelmalek
on 4 Aug 2014
To store your 8 matrices, use cell array
for i=2:9
coint{i}=[MainMatrix(:,1),MainMatrix(:,i)];
end
celldisp(coint)
2 Comments
Andrea Vandin
on 5 Jun 2020
This does not create a set of matrices. This creates a list of matrices. Meaning that you might have replicas of the same matrix in each entry.
Just try initializing MainMatrix as: MainMatrix = ones(9,9);
All entries of coint will contain a copy of the same matrix.
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