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Question regarding matrix index
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Hi,
I've a following matrix:
[1 2 3 4 5;
3 inf 5 7 inf;
5 6 7 inf inf;
2 3 4 9 1]
I wanted to find the minimum element from the last column with its row and column. So my answer to the above matrix should be 1 (as it is the minimum in column 5), row = 4, column = 5. I dont know how to code this. Please help!
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Answers (3)
Sven
on 28 May 2014
Edited: Sven
on 28 May 2014
Hi jana,
Try this:
X = [1 2 3 4 5;
3 inf 5 7 inf;
5 6 7 inf inf;
2 3 4 9 1]
[val, rowNum] = min(X,1) % Take the minimum in 1st dimension (columns)
val =
1 2 3 4 1
rowNum =
1 1 1 1 4
As you can see, the minimum value of each column is in val, and the row that it corresponds to is in the rowNum variable.
To get only the last (end) column you can use:
[val, rowNum] = min(X(:,end))
val =
1
rowNum =
4
Image Analyst
on 28 May 2014
Edited: Image Analyst
on 28 May 2014
[minValueInLastCol, rowOfMin] = min(yourMatrix(:, end));
Or if you want the min in the last row (just for completeness in case you're interested):
[minValueInLastRow, colOfMin] = min(yourMatrix(end, :));
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Geoff Hayes
on 28 May 2014
If Z is your matrix from above, just do:
[minVal,minIdx] = min(Z(:,end));
This will return the minimum value in minVal and its index in that column in minIdx:
minVal =
1
minIdx =
4
You already know the column number (5, since last one) and the row number is simply minIdx.
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