How do I convert a time domain signal to frequency domain?
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I am having some problems converting a time domain signal into frequency domain--I don't have constant sampling time.
In time domain, is this the way to plot the graph?
value = [42007935 111212895 184546560 238219725 238219725 184546560 111212895 42007935]; time = [0, ,5,1.25,2, 2,5,5, 4, 4.5, 6, 7, 8 ];
plot (time, value);
X and/or Y arguments ignored.
Could anyone help me plot a signal that does not have constant time?
2 Comments
Star Strider
on 12 May 2014
If you want to plot them, your time and value arrays have to have the same number of elements. They don’t.
dpb
on 12 May 2014
Edited: dpb
on 12 May 2014
Look for NUFFT (non-uniform FFT) literature -- there's quite a lot.
You surely have the sample times or at least delta-t's, don't you? W/o that you have nothing.
Don't believe TMW has an implementation packaged as yet, anyway.
ADDENDUM:
You might check the File Exchange for submissions and of course there's always a search including Matlab in the search.
Answers (2)
Vilnis Liepins
on 13 May 2014
Hello,
To convert nonuniform time domain data to frequency domain you can use Extended DFT (program NEDFT.m) available on fileexchange http://www.mathworks.com/matlabcentral/fileexchange/11020-extended-dft
NEDFT call line:
F=nedft(value,time,fn);
where frequencies [fn] could be generated as
fn=[-ceil((N-1)/2):floor((N-1)/2)]/N/T;
As I see from your example [time] data the mean sampling frequency T=1. The length of DFT N usually is set equal to or greater than the length(value) that, as Star Strider commented, should have the same dimensions as [time] array.
After that you also be able to get back constant time version of your data [value1] by applying IFFT to the result of NEDFT, call line:
value1=real(ifft(fftshift(F)));
Vilnis Liepins
on 19 May 2014
Edited: Vilnis Liepins
on 19 May 2014
Actually they are specified in your post:
>> value = [42007935 111212895 184546560 238219725 238219725 184546560 111212895 42007935];
>> time = [0, ,5,1.25,2, 2,5,5, 4, 4.5, 6, 7, 8 ];
Note that you need to correct the 'time' vector: time(1)<time(2)<time(3)<... and length(value) must be equal to length(time):
- the signal value(1)=42007935 is taken at time(1),
- the signal value(2)=111212895 is taken at time(2), and so on.
8 Comments
dpb
on 28 May 2014
It's about four or five comments past...you only need to use the
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button to see the previous that have been collapsed by the viewer by default.
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