summation operation in matlab
3 views (last 30 days)
Show older comments
hello, i am trying to write a code to implement the summation operation but having errors the equation is below. my code is
A=rand(1,10);
N = 6;
for b = 1:N
syms A;
Pb = (A.^N/factorial(N)) / symsum ((A.^i)/(factorial(i)),i,0,N);
% Bp = (Toi.^N)/(factorial(N)) / symsum(Toi.^[0:N]./ factorial([0:N]));
end
and i keep getting this error
??? Error using ==> factorial at 17
N must be a matrix of non-negative integers.
Error in ==> ERLANGB_TEST at 7
Pb = (A.^N/factorial(N)) / symsum ((A.^i)/(factorial(i)),i,0,N);
thanks for your anticipated help.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/158495/image.png)
2 Comments
Salaheddin Hosseinzadeh
on 13 Mar 2014
What is this in your quesion?
% Bp = (Toi.^N)/(factorial(N)) / symsum(Toi.^[0:N]./ factorial([0:N]));
end
thanks
Answers (3)
Mischa Kim
on 13 Mar 2014
Joe, use
syms A ii
N = 6;
Pb = A^N/factorial(N)/(symsum(A^ii/factorial(ii),0,N)); % symbolic expression
sPb = subs(Pb,A,3); % substitute 3 for A to get numeric result
1 Comment
Mischa Kim
on 14 Mar 2014
What release are you working with?
What happens when you replace in the equation
factorial(N)
by
sym('N!')
Marta Salas
on 14 Mar 2014
Edited: Marta Salas
on 14 Mar 2014
You must define i as a symbolic variable too, otherwise i is defined as the sqrt(-1)
syms A i
N = 6;
Pb = (A.^N/factorial(N)) / symsum ((A.^i)/factorial(i),i,0,N);
0 Comments
See Also
Categories
Find more on Calculus in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!