Find the first column in a matrix that contains at least 1 non zero..

Hi,im trying to find the first column in a matrix that contain at least 1 non zero. then the function Findfirst should return me with the column number that refers to the leftmost column in a matrix that contains at least a non zero element. below is my code but i dont seem to get the right results can anybody help me in identifying my error?

function [p] = Findfirst(A,currentRow) [m n]=size(A); p=1; for i=currentRow:m; for j=1:n; if A(i,j)~=0 p=i; if p<n p=n else p=n+1; end

end end end

Answer 1

[Mischa Kim]

Austin, here you go:

 function [p] = Findfirst(A,currentRow)
 [m n]=size(A);
 p=n;
 for i=currentRow:m
     for j=1:n
         if A(i,j)~=0
             p=j;       % you wanted to get the col index, right?
             break;     % break out once you have your solution
         end
     end
 end
 end

A bit more compact...

 function [p] = Findfirst(A)

 p = [];
 for ii = 1:length(A(1,:))
     if ~isempty(find(A(:,ii)))
         p = ii;
         break;
     end
 end
 end

For small-size matrices you could also

 [r c] = find(A);
 p = min(c);

[Austin]

It works,Thanks Alot bro!