How to store "for loop" values?
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Hi, I'm running the following code:
h=11:-1:-12
for i = 1:length(h)
beta=asind(cosd(Lat)*cosd(delta)*cosd(15*h)+sind(Lat)*sind(delta))
phi_s=asind((cosd(delta)*sind(15*h))/cosd(beta));
theta=acosd(cosd(beta)*cos(phi_s-phi_c)*sind(tilt)+sind(beta)*cosd(tilt));
I_bc=DNI*cosd(theta)
I_rc=GHI*reflectance*((1-cosd(tilt))/2);
I_dc=DHI*((1+cosd(tilt))/2);
I_c(i)=I_bc+I_dc+I_rc
end
figure(1)
plot(I_c)
hold on
Basically, I want h to decrement by 1 each time. I want the loop to calculate beta, phi_s, theta and calculate I_bc. I want this value of I_bc added to I_rc and I_dc, plot that sum, and repeat the loop.
What am I doing wrong? I realize I'm supposed to index each loop somehow, but I'm not quite sure how to do so...Can you help me?
Thanks
0 Comments
Accepted Answer
Amit
on 30 Jan 2014
Edited: Amit
on 30 Jan 2014
h=11:-1:-12
for i = 1:length(h)
beta=asind(cosd(Lat)*cosd(delta)*cosd(15*h(i))+sind(Lat)*sind(delta))
phi_s=asind((cosd(delta)*sind(15*h(i)))/cosd(beta));
theta=acosd(cosd(beta)*cos(phi_s-phi_c)*sind(tilt)+sind(beta)*cosd(tilt));
I_bc=DNI*cosd(theta)
I_rc=GHI*reflectance*((1-cosd(tilt))/2);
I_dc=DHI*((1+cosd(tilt))/2);
I_c(i)=I_bc+I_dc+I_rc
end
figure(1)
plot(I_c)
hold on
Even though you were looping for each value of h, you were using the whole h vector. I replaced h with h(i) for each loop. Now you'll get a scalar for each loop and store it.
2 Comments
Amit
on 30 Jan 2014
This is the same code you posted in question. I have posted the answer with some modifications which I think will take care of the issue.
More Answers (1)
Image Analyst
on 30 Jan 2014
Take a look at this syntax:
h=11:-1:-12
for i = h
disp(i);
end
A little bit out of the ordinary compared to your typical for loop, but perfectly valid MATLAB code. i takes on every value that h does. Then you'd just use i everywhere you're currently using h. That said, I usually do it the way Amit did it rather than this way.
2 Comments
Amit
on 30 Jan 2014
Actually, I just told him the mistake in his code without modifying it too much.
I, as well you (I am pretty sure), would do this without loop. This can be easily vectorized.
Image Analyst
on 30 Jan 2014
Correct. I was just alerting him and others to a not-so-well-known way of doing for loops.
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